layout: post title: 1.4 Correcting errors description: Practice with identifying and correcting code blocks type: ccc author: Safin Singh and Rohan Juneja permalink: /basics/js-debug hide: True —
Home | HTML | Data Types | DOM | JavaScript | JS Debugging |
Identifying and Correcting Errors (Unit 1.4)
Become familiar with types of errors and strategies for fixing them
- Review CollegeBoard videos and take notes on blog
- Complete assigned MCQ questions if applicable
Code Segments
Practice fixing the following code segments!
Segment 1: Alphabet List
Intended behavior: create a list of characters from the string contained in the variable alphabet
Code:
%%js
var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];
for (var i = 0; i < 26; i++) {
alphabetList.push(alphabet.charAt(i));
}
console.log(alphabetList);
<IPython.core.display.Javascript object>
What I Changed
I changed and added alphabet.charAt into the alphabetList.push to creaye spaces inbetween each letter and seperate them by individual characters instead of just being the entire alphabet at once.
Segment 2: Numbered Alphabet
Intended behavior: print the number of a given alphabet letter within the alphabet. For example:
"_" is letter number _ in the alphabet
Where the underscores (_) are replaced with the letter and the position of that letter within the alphabet (e.g. a=1, b=2, etc.)
Code:
%%js
var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];
for (var i = 0; i < 26; i++) {
alphabetList.push(alphabet.charAt(i));
}
console.log(alphabetList);
// Copy your previous code to built alphabetList here
let letterNumber = 5
for (var i = 0; i < alphabetList.length ; i++) {
if (i === letterNumber-1) {
console.log(alphabetList[letterNumber-1] + " is letter " + letterNumber + " in the alphabet")
}
}
// Should output:
// "e" is letter number 5 in the alphabet
<IPython.core.display.Javascript object>
What I Changed
I changed…
Segment 3: Odd Numbers
Intended behavior: print a list of all the odd numbers below 10
Code:
%%js
let evens = [];
let i = 1;
while (i <= 10) {
evens.push(i);
i += 2;
}
console.log(evens);
<IPython.core.display.Javascript object>
What I Changed
I changed…
BELOW NOT EDITED
The intended outcome is printing a number between 1 and 100 once, if it is a multiple of 2 or 5
- What values are outputted incorrectly. Why?
- Make changes to get the intended outcome.
%%js
var numbers = []
var newNumbers = []
var i = 0
while (i < 100) {
numbers.push(i)
i += 1
}
for (var i of numbers) {
if (numbers[i] % 5 === 0)
newNumbers.push(numbers[i])
if (numbers[i] % 2 === 0)
newNumbers.push(numbers[i])
if (numbers[i] % 5 != 5)
newNumbers.push(numbers[i])
}
console.log(newNumbers)
<IPython.core.display.Javascript object>
Challenge
This code segment is at a very early stage of implementation.
- What are some ways to (user) error proof this code?
- The code should be able to calculate the cost of the meal of the user
Hint:
- write a “single” test describing an expectation of the program of the program
- test - input burger, expect output of burger price
- run the test, which should fail because the program lacks that feature
- write “just enough” code, the simplest possible, to make the test pass
Then repeat this process until you get program working like you want it to work.
%%js
var menu = {
"burger": 3.99,
"fries": 1.99,
"drink": 0.99
};
var total = 0;
// Function to display the menu and calculate the cost of selected items
function calculateCost(item) {
if (menu.hasOwnProperty(item)) {
total += menu[item];
console.log(item + " added to the order. Total cost: $" + total.toFixed(2));
} else {
console.log("Sorry, " + item + " is not on the menu.");
}
}
// Test Case 1: Input "burger"
calculateCost("burger"); // This should add the price of the burger to the total and print the total cost.
// Display the updated total cost
console.log("Total cost of the meal: $" + total.toFixed(2));
<IPython.core.display.Javascript object>
Hacks
- Fix the errors in the first three segments in this notebook and say what you changed in the code cell under “What I Changed” (Challenge is optional)